344. 反转字符串（Easy）-白红宇

344. 反转字符串（Easy）

阅读量：568 次

发布时间：2019-03-09

本文共 239 字，大约阅读时间需要 1 分钟。

题目：编写一个函数，交换输入字符串中的前i个字符和后i个字符的位置，使得整个字符串对称。

我的题解：以下是我一个简洁的解法：

class Solution {

public void reverseString(char[] s) {

char tmp;

for (int i = 0; i < s.length/2; i++) {

tmp = s[i];

s[i] = s[s.length - 1 - i];

s[s.length - 1 - i] = tmp;

}

}

}

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